# card53

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I stumbled across a interesting thing with multiplications.

( x+1 ) ^2= ( x.x ) + ( x+x+1 )

When you square any number(lets call this number "X") the results between "X" and the next number in X's course squared is always a odd number that is doubled X's seperate result plus one. Uhh...errr....
4^2 = 16
5^2 = 25 ( 25-16=9 )
6^2 = 36 ( 36-25=11 )
7^2 = 49 ( 49-36=13 )
8^2 = 64 ( 64-49=15 )
Etc, etc...

So if X=15,
( 15+1 ) ^2 = ( 15x15 ) + ( 15+15+1 )
16^2 = ( 15x15 ) + ( 15+15+1 )
16^2 = 225 + ( 15+15+1 )
16^2 = 225 + 31
16^2 = 256

If X=3,
( 3+1 ) ^2 = ( 3x3 ) + ( 3+3+1 )
4^2 = ( 3x3 ) + ( 3+3+1 )
4^2 = 9 + ( 3+3+1 )
4^2 = 9 + 7
4^2 = 16

Anyways, I figure just having this formula on the card was boring so I drew Streetlights rampaging the streets with lasers shooting out of their fixtures.

::Edit::
I first written the formula out like this:
( x . x ) +x+x+1 = ( x+1 )( x+1 )

I then tried to clean it up a little bit:
( x+1 )^2 = ( x.x ) + ( x+x+1 )

Plus I have another variation to this that adds two to X's number instead of one:
( x+2 )^2 = x^2 + 4x + 4
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