Sierpinski Temple

19 25 4K (1 Today)

By MakinMagic |

Published: Dec 24, 2007

Created using Ultrafractal.

Another inspired by Dirk Monteny's work.

Image size

768x768px 197.53 KB

Comments25

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JoseSantosBrazil

Looks like the Jain Temple in Rajastan, India.

Nov 22, 2014

dark-beamStudent Artist

A true wonder! If only I can do this with simple kifs.

The M3 formula kifs;

Menger3(x,y,z){
r=x*x+y*y+z*z;
for(i=0;i<MI && r<bailout;i++){
rotate1(x,y,z);

x=abs(x);y=abs(y);z=abs(z);
if(x-y<0){x1=y;y=x;x=x1;}
if(x-z<0){x1=z;z=x;x=x1;}
if(y-z<0){y1=z;z=y;y=y1;}

rotate2(x,y,z);

x=scale*x-CX*(scale-1);
y=scale*y-CY*(scale-1);
z=scale*z;
if(z>0.5*CZ*(scale-1)) z-=CZ*(scale-1);

r=x*x+y*y+z*z;
}
return (sqrt(x*x+y*y+z*z)-2)*scale^(-i);
}

(possible?)

Mar 17, 2011

MakinMagicHobbyist Digital Artist

The Sierpinski Temple itself (exactly as in my full IFS render) can't be (completely) done using KIFS because apart from the (4*3 squares) Menger Carpet style base there are two (possibly 3, I forget) transforms above the "ground" and these are overlapping in terms of their sub-spaces which means that a single linear iteration will not always choose the correct transformation combination and therefore a tree-style iteration is required, though admittedly the tree could be limited to branching in the cases where more than one of the overlapping transforms could apply, rather than is done in my current 3D IFS formula for UF where the full tree is traversed with n branches per iteration where there are n transforms.
Having said that, in this case very careful use of the conditionals in a KIFS formula should be able to get reasonably close I would have thought.

Mar 17, 2011

dark-beamStudent Artist

Omg, I have enouhh troubles with the normal transforms! i better stay away

Mar 17, 2011