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dziadek1990's avatar


:D Remember kids: procrastination is a very bad thing. Just look how rarely I upload stuff!

>.> 've been fighting with my laziness for far too long...

I already noticed a small orthographical mistake. I guess I'll re-upload the file when I find a few more imperfections, so I don't keep re-uploading it after each minor correction.


Seasons 1-3 screentime analysis: [link]
Ponyville population analysis: [link]
Pony size and mass estimation: [link]
Life, death, sex, pregnancy and birth: [link]

Screentime analysis paper fallout: [link]
Binary Mane 6 Picture: [link]
© 2013 - 2021 dziadek1990
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labba94's avatar
I study math at university, but English is not my native language, so this is my only obstacle xD But I kind of understood both the point of the thing and (primarily) the mathematics behind it.

But speaking about math... =D As I can see, your formulas use a T - E as denominator of a fraction and then inside a logarithm: both of them have no sense for T - E = 0, thus meaning your formula doesn't work for T = E. It was also obvious from the final forum of the expression of the function, since the value "E" is out of the codomain (it could be reached only if A · e-kt were zero, but an exponential function cannot equal zero for any value of its exponent); so... does this mean that an object will never reach the same temperature as the one of the environment it is placed in? Or just that the formula doesn't work if you consider an object whose initial temperature is the same as the one of the environment?

Or... both of them? =P
dziadek1990's avatar
A = T(0) - E
For T(0) = E, T(t) = E -- so the formula works.

For T(0) <> E, T(t) will reach E for t equal infinity.
labba94's avatar
The second option kind of sums up what I thought, that is... reaching "E" for t equal infinity means that the object will reach the temperature of the environment in an infinite time (that is... never).

While for the first objection I agree with you ^^
dziadek1990's avatar
The T-never-reaching-exact-value-of-E sounds correct to me. Very intuitive.

The closer the temperatures, the slower the change of temperature of an object.

Temperatures of object and an environment could be VERY similar, but not the same, and we wouldn't realize it, because termometers have limited accuracy.

That's why it is easy to think that they eventually become equal.
labba94's avatar
Yes, taking into account the accuracy of the termometers the reasoning becomes correct. The difference is that I did not (and I still don't) think as a physicist... but as a mathematician xD

Still, I did not say it before, but... very great work, congratulations! =D
Pony-Berserker's avatar

Nieźle. Ja nie mam głowy do takich rzeczy :P Wierzę na słowo.
dziadek1990's avatar
Cieszę się, że moja ewentualna pomyłka w obliczeniach nie ma żadnych poważnych konsekwencji, bo gdyby każdy ze wszystkim miałby wierzyć na słowo, to... O_o

A co dopiero gdybym miał jakiś matematyczny zawód w którym od poprawności moich obliczeń miałoby zależeć życie ludzkie.
Miretz's avatar
This is so funny and geeky, I love it! XD
dziadek1990's avatar

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